HR Data Base MySQL Restricting and Sorting Data statement exercises.
출처: https://www.w3resource.com/mysql-exercises/restricting-and-sorting-data-exercises/
1. Write a query to display the name (first_name, last_name) and salary for all employees whose salary is not in the range $10,000 through $15,000.
- select first_name, last_name, salary from employees where salary not between 10000 and 15000;
2. Write a query to display the name (first_name, last_name) and department ID of all employees in departments 30 or 100 in ascending order.
- select first_name, last_name, department_id
from employees
where department_id = 30
or department_id = 100
order by department_id asc;
- select first_name, last_name, department_id
from employees
where department_id in (30, 100)
order by epartment_id asc;
3. Write a query to display the name (first_name, last_name) and salary for all employees whose salary is not in the range $10,000 through $15,000 and are in department 30 or 100.
- select first_name, last_name, salary
from employees
where department_id in (30, 100)
and salary not between 10000 and 15000;
4. Write a query to display the name (first_name, last_name) and hire date for all employees who were hired in 1987.
- select concat(first_name,' ',last_name) "Name", hire_date from employees where hire_date like "%1987%";
- select concat(first_name,' ',last_name) "Name", hire_date from employees where hire_date like "1987%";
5. Write a query to display the first_name of all employees who have both "b" and "c" in their first name.
- select first_name from employees where first_name like "%b%" and first_name like "%c%";
6. Write a query to display the last name, job, and salary for all employees whose job is that of a Programmer or a Shipping Clerk, and whose salary is not equal to $4,500, $10,000, or $15,000.
- select last_name, job_id, salary
from employees
where job_id = 'IT_PROG'
or job_id = 'SH_CLERK'
and salary not in (4500, 10000, 15000);
- select last_name, job_id, salary
from employees
where job_id in ('IT_PROG', 'SH_CLERK')
and salary not in (4500, 10000, 15000);
7. Write a query to display the last name of employees whose names have exactly 6 characters.
- select last_name from employees where LENGTH(last_name) = 6;
- select last_name from employees where last_name like '______';
8. Write a query to display the last name of employees having 'e' as the third character.
- select last_name from employees where last_name like'__e%';
9. Write a query to display the jobs/designations available in the employees table.
- select distinct job_id from employees;
10. Write a query to display the name (first_name, last_name), salary and PF (15% of salary) of all employees.
- select concat(first_name, ' ', last_name) "Name", salary, salary * 0.15 "PF" from employees;
11. Write a query to select all record from employees where last name in 'BLAKE', 'SCOTT', 'KING' and 'FORD'.
- select * from employees where last_name in ('BLAKE', 'SCOTT', 'KING', 'FORD');