HR Data Base MySQL Restricting and Sorting Data statement exercises.

출처: https://www.w3resource.com/mysql-exercises/restricting-and-sorting-data-exercises/

 

1. Write a query to display the name (first_name, last_name) and salary for all employees whose salary is not in the range $10,000 through $15,000. 

- select first_name, last_name, salary from employees where salary not between 10000 and 15000;

 

2. Write a query to display the name (first_name, last_name) and department ID of all employees in departments 30 or 100 in ascending order.

- select first_name, last_name, department_id 

from employees 

where department_id = 30 

or department_id = 100 

order by department_id asc;

 

- select first_name, last_name, department_id

from employees

where department_id in (30, 100)

order by epartment_id asc;

 

3. Write a query to display the name (first_name, last_name) and salary for all employees whose salary is not in the range $10,000 through $15,000 and are in department 30 or 100. 

- select first_name, last_name, salary 

from employees 

where department_id in (30, 100)

and salary not between 10000 and 15000;

 

4. Write a query to display the name (first_name, last_name) and hire date for all employees who were hired in 1987.

- select concat(first_name,' ',last_name) "Name", hire_date from employees where hire_date like "%1987%";

- select concat(first_name,' ',last_name) "Name", hire_date from employees where hire_date like "1987%";

 

5. Write a query to display the first_name of all employees who have both "b" and "c" in their first name. 

- select first_name from employees where first_name like "%b%" and first_name like "%c%";

 

6. Write a query to display the last name, job, and salary for all employees whose job is that of a Programmer or a Shipping Clerk, and whose salary is not equal to $4,500, $10,000, or $15,000. 

- select last_name, job_id, salary 

from employees 

where job_id = 'IT_PROG' 

or job_id = 'SH_CLERK' 

and salary not in (4500, 10000, 15000);

 

- select last_name, job_id, salary 

from employees 

where job_id in ('IT_PROG', 'SH_CLERK') 

and salary not in (4500, 10000, 15000);

 

7. Write a query to display the last name of employees whose names have exactly 6 characters. 

- select last_name from employees where LENGTH(last_name) = 6;

- select last_name from employees where last_name like '______';

 

8. Write a query to display the last name of employees having 'e' as the third character. 

- select last_name from employees where last_name like'__e%';

 

9. Write a query to display the jobs/designations available in the employees table.

- select distinct job_id from employees;

 

10. Write a query to display the name (first_name, last_name), salary and PF (15% of salary) of all employees. 

- select concat(first_name, ' ', last_name) "Name", salary, salary * 0.15 "PF" from employees;

 

11. Write a query to select all record from employees where last name in 'BLAKE', 'SCOTT', 'KING' and 'FORD'.

- select * from employees where last_name in ('BLAKE', 'SCOTT', 'KING', 'FORD');